(3x^3+2x^2-4x+5)-(x^3-3x+4)=

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Solution for (3x^3+2x^2-4x+5)-(x^3-3x+4)= equation: 


Simplifying
(3x3 + 2x2 + -4x + 5) + -1(x3 + -3x + 4) = 0

Reorder the terms:
(5 + -4x + 2x2 + 3x3) + -1(x3 + -3x + 4) = 0

Remove parenthesis around (5 + -4x + 2x2 + 3x3)
5 + -4x + 2x2 + 3x3 + -1(x3 + -3x + 4) = 0

Reorder the terms:
5 + -4x + 2x2 + 3x3 + -1(4 + -3x + x3) = 0
5 + -4x + 2x2 + 3x3 + (4 * -1 + -3x * -1 + x3 * -1) = 0
5 + -4x + 2x2 + 3x3 + (-4 + 3x + -1x3) = 0

Reorder the terms:
5 + -4 + -4x + 3x + 2x2 + 3x3 + -1x3 = 0

Combine like terms: 5 + -4 = 1
1 + -4x + 3x + 2x2 + 3x3 + -1x3 = 0

Combine like terms: -4x + 3x = -1x
1 + -1x + 2x2 + 3x3 + -1x3 = 0

Combine like terms: 3x3 + -1x3 = 2x3
1 + -1x + 2x2 + 2x3 = 0

Solving
1 + -1x + 2x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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